The equation of the parabola whose vertex is (-1, -2), axis is vertical and which passes…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the parabola whose vertex is (-1, -2), axis is vertical and which passes through the point (3, 6), is
- \(x^{2}+2 x-2 y-3=0\)
- \(2 x^{2}=3 y\)
- \(x^{2}-2 x+3 y=0\)
- \(x^{2}-2 x-2 y-3=0\)
Answer
(D) x^ 2 -2 x-2 y-3=0
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