The locus of the centre of a circle, which touches externally the circle x^ 2 +y^ 2 -6…

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. \(\mathbf{x}^{2}-6 \mathbf{x}-10 \mathbf{y}+14=0\)
2. \(x^{2}-10 x-6 y+14=0\)
3. \(y^{2}-6 x-10 y+14=0\)
4. \(y^{2}-10 x-6 y+14=0\)

Answer

(D) y^ 2 -10 x-6 y+14=0

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