The locus of the foot of perpendicular drawn from the centre of the ellipse x 2 + 3y 2 =…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The locus of the foot of perpendicular drawn from the centre of the ellipse x2 + 3y2 = 6 on any tangent to it is :
- (x2 + y2)2 = 6x2 – 2y2
- (x2 – y2)2 = 6x2 + 2y2
- (x2 – y2)2 = 6x2 – 2y2
- (x2 + y2)2 = 6x2 + 2y2
Answer
(D) (x 2 + y 2 ) 2 = 6x 2 + 2y 2
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