The slope of the common tangent to the ellipse x^ 2 a^ 2 + y^ 2 b^ 2 =1 and a concentric…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The slope of the common tangent to the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) and a concentric circle of radius r is,
- \(\tan ^{-1}\left(\sqrt{\frac{r^{2}-b^{2}}{a^{2}-r^{2}}}\right)\)
- \(\sqrt{\frac{r^{2}-b^{2}}{a^{2}-r^{2}}}\)
- \(\left(\frac{r^{2}-b^{2}}{a^{2}-r^{2}}\right)\)
- \(\sqrt{\frac{a^{2}-r^{2}}{r^{2}-b^{2}}}\)
Answer
(B) r^ 2 -b^ 2 a^ 2 -r^ 2
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