The distance of a point on ellipse x^ 2 6 + y^ 2 2 =1 from its centre is 2. The eccentric…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The distance of a point on ellipse \(\frac{x^{2}}{6}+\frac{y^{2}}{2}=1\) from its centre is 2. The eccentric angle of the point will be
- \(\frac{\pi}{4} \text { or } \frac{\pi}{3}\)
- \(\frac{\pi}{3} \text { or } \frac{3 \pi}{5}\)
- \(\frac{\pi}{4} \text { or } \frac{3 \pi}{4}\)
- None of these
Answer
(C) 4 or 3 4
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