Two vertices of an equilateral triangle are (–1, 0) and (1, 0), and its third vertex lies…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

Two vertices of an equilateral triangle are (–1, 0) and
(1, 0), and its third vertex lies above the x-axis. Then the equation of the circumcircle of the triangle is :
  1. x2 + y2 = 1
  2. \(\sqrt{3}\)(x2 + y2) + 2y –\(\sqrt{3}\) = 0
  3. \(\sqrt{3}\)(x2 + y2) – 2y –\(\sqrt{3}\) = 0
  4. none of these

Answer

(C) 3 (x 2 + y 2 ) – 2y – 3 = 0

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