Two vertices of an equilateral triangle are (–1, 0) and (1, 0), and its third vertex lies…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Two vertices of an equilateral triangle are (–1, 0) and
(1, 0), and its third vertex lies above the x-axis. Then the equation of the circumcircle of the triangle is :
(1, 0), and its third vertex lies above the x-axis. Then the equation of the circumcircle of the triangle is :
- x2 + y2 = 1
- \(\sqrt{3}\)(x2 + y2) + 2y –\(\sqrt{3}\) = 0
- \(\sqrt{3}\)(x2 + y2) – 2y –\(\sqrt{3}\) = 0
- none of these
Answer
(C) 3 (x 2 + y 2 ) – 2y – 3 = 0
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