The straight lines x+y=0,3 x+y-4=0 and x+3 y-4=0 form a triangle which is,
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The straight lines \(x+y=0,3 x+y-4=0\) and \(x+3 y-4=0\) form a triangle which is,
- right angled
- equilateral
- isosceles
- None of these
Answer
(C) isosceles
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If the line y =x +3 meets the circle x 2 + y 2 = a 2 at A and B, then the equation of the circle having AB as…
- The name of the curve described parametrically by the equations x = t 2 + t + 1, y = t 2 – t + 1 is
- The line joining two points A (2, 0); B (3, 1) is rotated about A in the anticlockwise direction through an…
- A point on the parabola y 2 = 18x at which the ordinate increases at twice the rate of the abscissa is
- If P is a moving point in the xy–plane in such a way that perimeter of triangle PQR is 16 where Q ≡ (3, 5 )…
- The distance of the line 2 x-3 y=4 from the point (1, 1) measured parallel to the line x+y=1 is,
- The equation of a circle which passes through the point (1, –2) and (4, –3) and whose centre lies on the line…
- The abscissae and ordinates of the points A and B are the roots of the equations x 2 + 2ax + b = 0 and x 2 +…
More Co-ordinate Geometry questions · Browse all practice questions