The abscissae and ordinates of the points A and B are the roots of the equations x 2 +…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The abscissae and ordinates of the points A and B are the roots of the equations x2 + 2ax + b = 0 and
x2 + 2cx + d = 0 respectively, then the equation of circle with AB as diameter is
x2 + 2cx + d = 0 respectively, then the equation of circle with AB as diameter is
- x2 + y2 + 2ax + 2cy + b + d = 0
- x2 + y2 – 2ax – 2cy – b – d = 0
- x2 + y2 – 2ax – 2cy + b + d = 0
- x2 + y2 + 2ax + 2cy – b – d = 0
Answer
(A) x 2 + y 2 + 2ax + 2cy + b + d = 0
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