Find the equation of tangents to the ellipse 4 x^ 2 +3 y^ 2 =5 , which are parallel to…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Find the equation of tangents to the ellipse \(4 x^{2}+3 y^{2}=5\), which are parallel to the line \(3 x-y+7=0\).
- \(y=3 x+5\)
- \(y=3 x \pm \sqrt{\frac{15}{7}}\)
- \(y=3 x \pm \sqrt{\frac{155}{12}}\)
- None of these
Answer
(C) y=3 x 155 12
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The equation of two straight lines through (7, 9) and making an angle of 60° with the line x- 3 y-2 3 =0 is :
- The equation of a circle which passes through the three points (3, 0), (1, –6), (4, –1) is-
- The equation of the tangent to the parabola y 2 = 4ax at point (a/t 2 , 2a/t) is
- The equations of the lines through (–1, –1) and making angles 45° with the line x + y = 0 are
- The equation of a line through the point (–4, –3) and parallel to x-axis, is
- A circle of radius r is concentric with an ellipse x ^ 2 a ^ 2 + y ^ 2 ~b ^ 2 =1 . If common tangent is…
- The parametric equation of the curve (y – 2) 2 = 12 (x – 4) are–
- If the vertices P, Q, R of a Δ PQR are rational points, which of the following points of the Δ PQR is/are…
More Co-ordinate Geometry questions · Browse all practice questions