The equation of a circle which passes through the three points (3, 0), (1, –6), (4, –1)…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The equation of a circle which passes through the three points (3, 0), (1, –6), (4, –1) is-
  1. 2x2 + 2y2 + 5x – 11y + 3 = 0
  2. x2 + y2 – 5x + 11y – 3 = 0
  3. x2 + y2 + 5x – 11y + 3 = 0
  4. 2x2 + 2y2 – 5x + 11y – 3 = 0

Answer

(D) 2x 2 + 2y 2 – 5x + 11y – 3 = 0

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Co-ordinate Geometry questions · Browse all practice questions