The equation of a circle which passes through the three points (3, 0), (1, –6), (4, –1)…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of a circle which passes through the three points (3, 0), (1, –6), (4, –1) is-
- 2x2 + 2y2 + 5x – 11y + 3 = 0
- x2 + y2 – 5x + 11y – 3 = 0
- x2 + y2 + 5x – 11y + 3 = 0
- 2x2 + 2y2 – 5x + 11y – 3 = 0
Answer
(D) 2x 2 + 2y 2 – 5x + 11y – 3 = 0
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