The equation of the ellipse which passes through origin and has its foci at the points…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The equation of the ellipse which passes through origin and has its foci at the points (1, 0) and (3, 0) is -
  1. 3x2 + 4y2 = x
  2. 3x2 + y2 = 12x
  3. x2 + 4y2 = 12x
  4. 3x2 + 4y2 = 12x

Answer

(D) 3x 2 + 4y 2 = 12x

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Co-ordinate Geometry questions · Browse all practice questions