The equation of the ellipse which passes through origin and has its foci at the points…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the ellipse which passes through origin and has its foci at the points (1, 0) and (3, 0) is -
- 3x2 + 4y2 = x
- 3x2 + y2 = 12x
- x2 + 4y2 = 12x
- 3x2 + 4y2 = 12x
Answer
(D) 3x 2 + 4y 2 = 12x
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