The abscissas and ordinates of the points A and B are the roots of the equations x^ 2 +2…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The abscissas and ordinates of the points A and B are the roots of the equations \(x^{2}+2 a x+b=0 \text { and } x^{2}+2 c x+d=0\) respectively. Then, the equation of circle with AB as diameter, is

  1. \(x^{2}+y^{2}+2 a x+2 c y+b+d=0\)
  2. \(x^{2}+y^{2}-2 a x-2 c y-b-d=0\)
  3. \(x^{2}+y^{2}+2 a x+2 c y-b-d=0\)
  4. None of these

Answer

(C) x^ 2 +y^ 2 +2 a x+2 c y-b-d=0

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