The abscissas and ordinates of the points A and B are the roots of the equations x^ 2 +2…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The abscissas and ordinates of the points A and B are the roots of the equations \(x^{2}+2 a x+b=0 \text { and } x^{2}+2 c x+d=0\) respectively. Then, the equation of circle with AB as diameter, is
- \(x^{2}+y^{2}+2 a x+2 c y+b+d=0\)
- \(x^{2}+y^{2}-2 a x-2 c y-b-d=0\)
- \(x^{2}+y^{2}+2 a x+2 c y-b-d=0\)
- None of these
Answer
(C) x^ 2 +y^ 2 +2 a x+2 c y-b-d=0
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