The centre of a circle passing through the points (0, 0), (1, 0) and touching the circle…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The centre of a circle passing through the points (0, 0),
(1, 0) and touching the circle x2 + y2 = 9 is :
(1, 0) and touching the circle x2 + y2 = 9 is :
- (3/2, 1/2)
- (1/2, 3/2)
- (1/2, 1/2)
- \(\left(\frac{1}{2} \pm \sqrt{2}\right)\)
Answer
(D) ( 1 2 2 )
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