The equation of the circle with centre (2, 1) and touching the line 3 x+4 y=5 is,
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the circle with centre (2, 1) and touching the line \(3 x+4 y=5\) is,
- \(x^{2}+y^{2}-4 x-2 y+5=0\)
- \(x^{2}+y^{2}-4 x-2 y-5=0\)
- \(x^{2}+y^{2}-4 x-2 y+4=0\)
- \(x^{2}+y^{2}-4 x-2 y-4=0\)
Answer
(D) x^ 2 +y^ 2 -4 x-2 y-4=0
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