The equation of the hyperbola in the standard form (with transverse axis along the…

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. \(\frac{x^{2}}{16}-\frac{y^{2}}{18}=1\)
2. \(\frac{x^{2}}{36}-\frac{y^{2}}{27}=1\)
3. \(\frac{x^{2}}{64}-\frac{y^{2}}{36}=1\)
4. \(\frac{x^{2}}{36}-\frac{y^{2}}{64}=1\)

Answer

(B) x^ 2 36 - y^ 2 27 =1

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