The value of m, for which the line y=m x+ 25 3 3 is a normal to the conic x^ 2 16 - y^ 2…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The value of m, for which the line \(y=m x+\frac{25 \sqrt{3}}{3}\) is a normal to the conic \(\frac{x^{2}}{16}-\frac{y^{2}}{9}=1\) is,
- \(\pm \frac{2}{\sqrt{3}}\)
- \(\sqrt{3}\)
- \(-\frac{\sqrt{3}}{2}\)
- None of these
Answer
(D) None of these
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