The circles x 2 + y 2 + 6x + 6y = 0 and x 2 + y 2 – 12x – 12y =0
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The circles x2 + y2 + 6x + 6y = 0 and x2 + y2 – 12x – 12y =0
- touch each other internally
- touch each other externally
- intersect in two points
- cut orthogonally
Answer
(B) touch each other externally
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The circle x 2 + y 2 – 3x – 4y + 2 = 0 cuts x-axis at
- If and are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of…
- The number of common tangents to the circles x^ 2 +y^ 2 =4 and x^ 2 +y^ 2 -6 x-8 y=24 is,
- If the two circles (x – 1) 2 + (y – 3) 2 = r 2 and x 2 + y 2 – 8x + 2y + 8 = 0 intersect in two distinct…
- Find the area of region bounded by the curve x^ 2 -4 x+y^ 2 =0 .
- If the eccentricity of the standard hyperbola passing through the point (4, 6) is 2, then the equation of the…
- The locus of a point which moves such that the line segment having end points (2, 0) and (–2, 0) subtend a…
- The line 5 x+12 y=9 touches the hyperbola x^ 2 -9 y^ 2 =9 at the point,
More Co-ordinate Geometry questions · Browse all practice questions