If the two circles (x – 1) 2 + (y – 3) 2 = r 2 and x 2 + y 2 – 8x + 2y + 8 = 0 intersect…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If the two circles (x – 1)2 + (y – 3)2 = r2 and
x2 + y2 – 8x + 2y + 8 = 0 intersect in two distinct points, then
x2 + y2 – 8x + 2y + 8 = 0 intersect in two distinct points, then
- r < 2
- r = 2
- r > 2
- 2 < r < 8
Answer
(D) 2 < r < 8
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