Find the equation of the hyperbola whose directrix is 2x + y = 1, focus (1, 2) and…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Find the equation of the hyperbola whose directrix is
2x + y = 1, focus (1, 2) and eccentricity\(\sqrt{3}\).
2x + y = 1, focus (1, 2) and eccentricity\(\sqrt{3}\).
- 7x2 – 2y2 + 12xy – 2x + 14y – 22 = 0
- 7x2 – 2y2 + 2xy – 2x + 14y – 22 = 0
- 7x2 – 2y2 + xy – 14x + 2y – 22 = 0
- none of the above
Answer
(A) 7x 2 – 2y 2 + 12xy – 2x + 14y – 22 = 0
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