One of the focus of the hyperbola 3(y – 1) 2 – 4 ( x – 2) 2 = 12 is

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. \((0, \sqrt{7})\)
2. \((2,1+\sqrt{7})\)
3. \((0,1-\sqrt{7})\)
4. \((0,-\sqrt{7})\)

Answer

(B) (2,1+ 7 )

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