The locus of the vertex of the family of parabolas y = a^ 3 x^ 2 3 + a^ 2 x 2 – 2a is
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The locus of the vertex of the family of parabolas
y = \(\frac{a^{3} x^{2}}{3}+\frac{a^{2} x}{2}\)– 2a is
y = \(\frac{a^{3} x^{2}}{3}+\frac{a^{2} x}{2}\)– 2a is
- xy = \(\frac{105}{6}\)
- xy = \(\frac{3}{4}\)
- xy = \(\frac{5}{6}\)
- xy = \(\frac{4}{105}\)
Answer
(A) xy = 105 6
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