The equation of the base of an equilateral triangle is x+y=2 and the vertex is (2, –1)…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the base of an equilateral triangle is \(x+y=2\) and the vertex is (2, –1). Length of its side is
then \(\frac{10}{l^{2}}\) equals
then \(\frac{10}{l^{2}}\) equals- 10
- 15
- 20
- 5
Answer
(B) 15
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The coordinates of a point on x + y + 3 = 0, whose distance from x + 2y + 2 = 0 is 5 is equal to -
- The parametric equation of the curve (y – 2) 2 = 12 (x – 4) are–
- The equation x^ 2 10-a + y^ 2 4-a =1 represents an ellipse, if
- One of the focus of the hyperbola 3(y – 1) 2 – 4 ( x – 2) 2 = 12 is
- The number of points outside the ellipse on its major axis from which a normal (other than the x-axis) can be…
- The parametric equation of a parabola is x = t 2 + 1, y = 2t + 1 . The Cartesian equation of its directrix is
- The equations of the lines through (–1, –1) and making angles 45° with the line x + y = 0 are
- Two vertices of an equilateral triangle are (–1, 0) and (1, 0), and its third vertex lies above the x-axis…
More Co-ordinate Geometry questions · Browse all practice questions