The equation of the circle passing through (1, 1) and the points of intersection of x^ 2…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the circle passing through (1, 1) and the points of intersection of \(x^{2}+y^{2}+13 x-3 y=0\) and \(2 x^{2}+2 y^{2}+4 x-7 y-25=0\) is,
- \(4 x^{2}+4 y^{2}-30 x-10 y=25\)
- \(4 x^{2}+4 y^{2}+30 x-13 y-25=0\)
- \(4 x^{2}+4 y^{2}-17 x-10 y+25=0\)
- None of the above
Answer
(C) 4 x^ 2 +4 y^ 2 -17 x-10 y+25=0
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