If two circles x^ 2 +y^ 2 =r^ 2 and x^ 2 +y^ 2 -10 x+16=0 intersect at two real points…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If two circles \(x^{2}+y^{2}=r^{2} \text { and } x^{2}+y^{2}-10 x+16=0\) intersect at two real points, then
- \(1
- \(3
- \(7
- \(7<1<8\)
- \(3
Answer
(A) 1<r<7
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