The equation to a circle passing through the origin and cutting of intercepts each equal…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The equation to a circle passing through the origin and cutting of intercepts each equal to 5 of the axes is-
  1. x2 + y2 + 5x – 5y = 0
  2. x2 + y2 – 5x + 5y = 0
  3. x2 + y2 – 5x – 5y = 0
  4. x2 + y2 + 5x + 5y = 0

Answer

(C) x 2 + y 2 – 5x – 5y = 0

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