The equation to a circle passing through the origin and cutting of intercepts each equal…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation to a circle passing through the origin and cutting of intercepts each equal to 5 of the axes is-
- x2 + y2 + 5x – 5y = 0
- x2 + y2 – 5x + 5y = 0
- x2 + y2 – 5x – 5y = 0
- x2 + y2 + 5x + 5y = 0
Answer
(C) x 2 + y 2 – 5x – 5y = 0
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