The equation of the normal to the ellipse x^ 2 a^ 2 + y^ 2 b^ 2 =1 at the positive end of…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the normal to the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) at the positive end of the latus rectum, is
- \(x+e y+e^{3} z=0\)
- \(\mathbf{x}-\mathbf{e y}-\mathbf{e}^{3} \mathbf{a}=0\)
- \(x-e y-e^{2} a=0\)
- None of these
Answer
(B) x - e y - e ^ 3 a =0
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