If p is the perpendicular from origin to the line x a + y b =1, then

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. \(\frac{1}{p^{2}}=\frac{1}{a^{2}}+\frac{1}{b^{2}}\)
2. \(\frac{1}{p^{2}}=\frac{1}{a^{2}}-\frac{1}{b^{2}}\)
3. \(\frac{1}{p^{2}}=-\frac{1}{p^{2}}-\frac{1}{b^{2}}\)
4. \(\frac{1}{p^{2}}=-\frac{1}{p^{2}}+\frac{1}{b^{2}}\)

Answer

(A) 1 p^ 2 = 1 a^ 2 + 1 b^ 2

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