If a sphere of constant radius 'k' passes through the origin and meets the axis in A, B…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If a sphere of constant radius \(\text { 'k' }\) passes through the origin and meets the axis in A, B, C then the centroid of the triangle ABC lies on :
- \(x^{2}+y^{2}+z^{2}=k^{2}\)
- \(x^{2}+y^{2}+z^{2}=4 k^{2}\)
- \(9\left[x^{2}+y^{2}+z^{2}\right]=4 k^{2}\)
- \(9\left[x^{2}+y^{2}+z^{2}\right]=k^{2}\)
Answer
(C) 9 [x^ 2 +y^ 2 +z^ 2 ]=4 k^ 2
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