The equation of the common tangents to the parabola y^ 2 =8 x and hyperbola 3 x^ 2 -y^ 2…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the common tangents to the parabola \(y^{2}=8 x\) and hyperbola \(3 x^{2}-y^{2}=3\) is,
- \(2 x \pm y+1=0\)
- \(\mathbf{x} \pm \mathbf{y}+1=0\)
- \(\mathbf{x} \pm \mathbf{2 y}+\mathbf{1}=\mathbf{0}\)
- \(x \pm y+z=0\)
Answer
(B) x y +1=0
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