The equation of sphere, concentric with the sphere 2 x^ 2 +2 y^ 2 +2 z^ 2 -6 x+2 y-4 z=1…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of sphere, concentric with the sphere \(2 x^{2}+2 y^{2}+2 z^{2}-6 x+2 y-4 z=1\) and double its radius, is
- \(x^{2}+y^{2}+z^{2}-x+y-z=1\)
- \(x^{2}+y^{2}+z^{2}-6 x+2 y-4 z=1\)
- \(2 x^{2}+2 y^{2}+2 z^{2}-6 x+2 y-4 z-15=0\)
- \(2 x^{2}+2 y^{2}+2 z^{2}-6 x+2 y-4 z-25=0\)
Answer
(D) 2 x^ 2 +2 y^ 2 +2 z^ 2 -6 x+2 y-4 z-25=0
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