The equation of sphere, concentric with the sphere 2 x^ 2 +2 y^ 2 +2 z^ 2 -6 x+2 y-4 z=1…

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The equation of sphere, concentric with the sphere \(2 x^{2}+2 y^{2}+2 z^{2}-6 x+2 y-4 z=1\) and double its radius, is
  1. \(x^{2}+y^{2}+z^{2}-x+y-z=1\)
  2. \(x^{2}+y^{2}+z^{2}-6 x+2 y-4 z=1\)
  3. \(2 x^{2}+2 y^{2}+2 z^{2}-6 x+2 y-4 z-15=0\)
  4. \(2 x^{2}+2 y^{2}+2 z^{2}-6 x+2 y-4 z-25=0\)

Answer

(D) 2 x^ 2 +2 y^ 2 +2 z^ 2 -6 x+2 y-4 z-25=0

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