The equation of the common tangent to the parabola y^ 2 =2 x and x^ 2 =16 y will be
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the common tangent to the parabola \(y^{2}=2 x \text { and } x^{2}=16 y\) will be
- \(x+y+z=0\)
- \(\mathbf{x}-3 \mathbf{y}+1=0\)
- \(x+z y-z=0\)
- \(x+z y+z=0\)
Answer
(B) x -3 y +1=0
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