The equation of the common tangent to the parabola y^ 2 =2 x and x^ 2 =16 y will be

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The equation of the common tangent to the parabola \(y^{2}=2 x \text { and } x^{2}=16 y\) will be
  1. \(x+y+z=0\)
  2. \(\mathbf{x}-3 \mathbf{y}+1=0\)
  3. \(x+z y-z=0\)
  4. \(x+z y+z=0\)

Answer

(B) x -3 y +1=0

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Co-ordinate Geometry questions · Browse all practice questions