The eccentricity of the conjugate hyperbola of the hyperbola x 2 – 3y 2 = 1 is
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The eccentricity of the conjugate hyperbola of the hyperbola x2 – 3y2 = 1 is
- 2
- \(\frac{2}{\sqrt{3}}\)
- 4
- \(\frac{4}{3}\)
Answer
(A) 2
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