Equation of a circle concentric with the circle 2x 2 + 2y 2 – 6x + 8y + 1 = 0 and of…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Equation of a circle concentric with the circle
2x2 + 2y2 – 6x + 8y + 1 = 0 and of double its area is
2x2 + 2y2 – 6x + 8y + 1 = 0 and of double its area is
- 2x2 + 2y2 – 12x + 16y + 1 = 0
- 4x2 + 4y2 – 3x + 16y + 2 = 0
- 4x2 + 4y2 – 12x + 16y – 21 = 0
- None of these
Answer
(C) 4x 2 + 4y 2 – 12x + 16y – 21 = 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If the foot of the perpendicular from the origin to a straight line is at the point (3, –4). Then, the…
- The equation to the ellipse, whose focus is the point (–1, 1), whose directrix is the straight line x – y + 3…
- If the latus rectum of an ellipse is half of its minor axis, its eccentricity is
- If the lines x + 2ay + a = 0, x + 3by + b = 0 and x + 4cy + c = 0 are concurrent, then a, b and c are in
- If x_ 1 , x_ 2 , x_ 3 as well as V_ 1 , V_ 2 , V_ 3 are in GP with same common ratio, then the points P^ P…
- The number of points outside the ellipse on its major axis from which a normal (other than the x-axis) can be…
- The circle x 2 + y 2 – 3x – 4y + 2 = 0 cuts x-axis at
- From a fixed point A, three normals are drawn to the parabola ^ 2 = 4 a at the points P, Q and R. Two circles…
More Co-ordinate Geometry questions · Browse all practice questions