ABC is a variable triangle with the fixed vertex C(1,2) and A, B having the coordinates (…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
ABC is a variable triangle with the fixed vertex \(C(1,2)\) and A, B having the coordinates \(\left(\cos t_{1} \sin t\right),\left(\sin t_{1}-\cos t\right)\) respectively, where t is a parameter. Then locus of the centroid of the Δ ABC is,
- \(3\left(x^{2}+y^{2}\right)-2 x-4 y-1=0\)
- \(3\left(x^{2}+y^{2}\right)-2 x-4 y+1=0\)
- \(3\left(x^{2}+y^{2}\right)+2 x+4 y-1=0\)
- \(3\left(x^{2}+y^{2}\right)+2 x+4 y+1=0\)
Answer
(A) 3 (x^ 2 +y^ 2 )-2 x-4 y-1=0
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