The equation of director circle of the hyperbola x^ 2 16 - y^ 2 4 =1 is given by,
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of director circle of the hyperbola \(\frac{x^{2}}{16}-\frac{y^{2}}{4}=1\) is given by,
- \(x^{2}+y^{2}=16\)
- \(x^{2}+y^{2}=4\)
- \(x^{2}+y^{2}=20\)
- \(x^{2}+y^{2}=12\)
Answer
(B) x^ 2 +y^ 2 =4
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