If the two lines x+a-1) y=1 and 2 x+a^ 2 y=1(a R-(0,1) are perpendicular, then the…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If the two lines \(x+a-1) y=1 \text { and } 2 x+a^{2} y=1(a \in R-(0,1)\) are perpendicular, then the distance of their point of intersection from the origin is:
- \(\frac{2}{5}\)
- \(\sqrt{\frac{2}{5}}\)
- \(\frac{2}{\sqrt{5}}\)
- \(\frac{\sqrt{2}}{5}\)
Answer
(C) 2 5
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The point (sin θ, cos θ), θ being any real number, lie inside the circle x 2 + y 2 – 2x – 2y + λ = 0, if
- Let P be the point (1, 0) and Q a point on the locus y 2 = 8x. The locus of mid point of PQ is
- The equation of a tangent to the hyperbola 4 x^ 2 -5 y^ 2 =20 parallel to the line x-y=2 is:
- A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4…
- The intercept on the line y = x by the circle x^ 2 +y^ 2 -2 x=0 is AB. Equation of the circle on AB as a…
- A point on the parabola y 2 = 18x at which the ordinate increases at twice the rate of the abscissa is
- If the line a x+b y+c=0 is normal to the curve x y=1 , then
- The equation of the common tangent to the parabola y^ 2 =2 x and x^ 2 =16 y will be
More Co-ordinate Geometry questions · Browse all practice questions