Equation of the ellipse whose foci are (4, 0) and (–4, 0) and e = 1/3 is

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. x² /9 + y²/8 = 16
2. x²/8 + y²/9 = 16
3. x²/9 + y²/8 = 32
4. none of these

Answer

(A) x 2 /9 + y 2 /8 = 16

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• The circle x 2 + y 2 – 2x – 3ky – 2 = 0 passes through the fixed point :
• If the vertex = (2, 0) and the extremities of the latus rectum are (3, 2) and (3, –2), then the equation of…
• Equation of the tangent to the hyperbola 2 x^ 2 -3 y^ 2 =6 which is parallel to the line y-3 x-4=0 is,
• Two points (a, 0) and (0, b) are joined by a straight line. Another point on this line is
• Equation of a circle concentric with the circle 2x 2 + 2y 2 – 6x + 8y + 1 = 0 and of double its area is
• The tangent at an extremity (in the first quadrant) of latus rectum of the hyperbola x^ 2 4 - y^ 2 5 =1…
• A square of side a lies above the x-axis and has one vertex at the origin. The side passing through the…
• The curve represented by x = 2 (cos t + sin t), y = 5 (cos t – sin t) is

More Co-ordinate Geometry questions · Browse all practice questions