The circle x 2 + y 2 – 2x – 3ky – 2 = 0 passes through the fixed point :

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. \((1+\sqrt{3}, 0)\)
2. \((-1+\sqrt{3}, 0)\)
3. \((-\sqrt{3}-1,1)\)
4. \((1-\sqrt{3}, 1)\)

Answer

(A) (1+ 3 , 0)

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• If the point (-5+ 2 ,-3+ 2 ) is an interior point of the larger segement of the circles x 2 + y 2 = 16 cut…
• The equations of the tangents to the hyperbola x 2 – 4y 2 = 36 which are perpendicular to the line x – y + 4…
• The equation of the straight line which passes through the point of intersection of the straight lines x + 2y…
• The image of the point (2, 1) with respect to the line mirror be (5, 2). Then the equation of the mirror is -
• If the lines 3 x-4 y-7=0 and 2 x-3 y-5=0 are two diameters of a circle of area 49 square unit, then equation…
• Equation of the circle of radius 5 whose centre lies on y-axis in first quadrant and passes through (3, 2) is
• The equation of the base of an equilateral triangle is x+y=2 and the vertex is (2, –1). Length of its side is…
• The equation of the tangent to the parabola ^ 2 = 4 a at the point (3, 2) is,

More Co-ordinate Geometry questions · Browse all practice questions