Equation of the circle of radius 5 whose centre lies on y-axis in first quadrant and…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Equation of the circle of radius 5 whose centre lies on
y-axis in first quadrant and passes through (3, 2) is
y-axis in first quadrant and passes through (3, 2) is
- x2 + y2 – 12y + 11 = 0
- x2 + y2 – 6y – 1 = 0
- x2 + y2 – 8y + 3 = 0
- None of these
Answer
(A) x 2 + y 2 – 12y + 11 = 0
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