If the lines 3 x-4 y-7=0 and 2 x-3 y-5=0 are two diameters of a circle of area 49 square…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If the lines \(3 x-4 y-7=0 \text { and } 2 x-3 y-5=0\) are two diameters of a circle of area 49\(\pi\) square unit, then equation of the circle is
- \(x^{2}+y^{2}-2 x+2 y-47=0\)
- \(x^{2}+y^{2}+2 x-2 y-47=0\)
- \(x^{2}+y^{2}+2 x-2 y-62=0\)
- \(x^{2}+y^{2}-2 x+2 y-62=0\)
Answer
(D) x^ 2 +y^ 2 -2 x+2 y-62=0
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