The equation of the circle touches y axis and having centre (–2, –3) is

Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry

1. x² + y² – 4x – 9y – 4 = 0
2. x² + y² + 4x + 9y + 4 = 0
3. x² + y² + 4x + 6y + 9 = 0
4. x² + y² – 4x – 6y – 9 = 0

Answer

(C) x 2 + y 2 + 4x + 6y + 9 = 0

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