Let the equations of two sides of a triangle be 3 x-2 y+6=0 and 4 x+5 y-20=0 . If the…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Let the equations of two sides of a triangle be \(3 x-2 y+6=0\) and \(4 x+5 y-20=0\). If the orthocentre of this triangle is at (1, 1), then the equation of its third side is:
- 26x - 122y - 1675 = 0
- 26x + 61y + 1675 = 0
- 122y - 26x - 1675 = 0
- 122y + 26x + 1675 = 0
Answer
(C) 122y - 26x - 1675 = 0
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