The equation of the common tangent touching the circle (x-3)^ 2 +y^ 2 =9 and the parabola…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of the common tangent touching the circle \((x-3)^{2}+y^{2}=9\) and the parabola \(\forall^{2}\;=\;4\chi\) above the x-axis is,
- \(\sqrt{3} y=3 x+1\)
- \(\sqrt{3} y=-(x+3)\)
- \(\sqrt{3} y=(x+3)\)
- \(\sqrt{3} y=-(3 x+1)\)
Answer
(B) 3 y=-(x+3)
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