The centre of the circle passing through the point (0,1) and touching the curve y = x 2…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The centre of the circle passing through the point (0,1) and touching the curve y = x2 at (2, 4) is :
- \(\left(-\frac{6}{5}, \frac{2}{0}\right)\)
- \(\left(-\frac{6}{7}, \frac{3}{0}\right)\)
- \(\left(-\frac{5}{5}, \frac{3}{10}\right)\)
- none of these
Answer
(C) (- 5 5 , 3 10 )
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