The point P is equidistant from A(1, 3), B(- 3, 5) and C(5, - 1), then PA is equal to

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The point P is equidistant from A(1, 3), B(- 3, 5) and C(5, - 1), then PA is equal to
  1. 5
  2. \(5 \sqrt{5}\)
  3. 25
  4. \(5 \sqrt{10}\)

Answer

(D) 5 10

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