The ellipse x^ 2 25 + y^ 2 16 =1 and the hyperbola x^ 2 25 - y^ 2 16 =1 have in common
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The ellipse \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\) and the hyperbola \(\frac{x^{2}}{25}-\frac{y^{2}}{16}=1\) have in common
- centre only
- centre, foci and directrices
- centre, foci and vertices
- centre and vertices only
Answer
(A) centre only
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