If a circle passes though the point (a, b) and cuts the circle x^ 2 +y^ 2 =4…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If a circle passes though the point (a, b) and cuts the circle\(x^{2}+y^{2}=4\) orthogonally, then the locus of its centre is
- \(2 a x+2 b y+\left[a^{2}+b^{2}+4\right]=0\)
- \(2 a x+2 b y-\left[a^{2}+b^{2}+4\right]=0\)
- \(2 a x-2 b y+\left[a^{2}+b^{2}+4\right]=0\)
- \(2 a x-2 b y-\left[a^{2}+b^{2}+4\right]=0\)
Answer
(B) 2 a x+2 b y- [a^ 2 +b^ 2 +4 ]=0
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