The solution of the differential equation d y d x = y+x 2 y-x y is

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\sin ^{2} y=x \sin y+\frac{x^{2}}{2}+c\)
2. \(\sin ^{2} y=x \sin y-\frac{x^{2}}{2}+c\)
3. \(\sin ^{2} y=x+\sin y+\frac{x^{2}}{2}+c\)
4. \(\sin ^{2} y=x-\sin y+\frac{x^{2}}{2}+c\)

Answer

(B) ^ 2 y=x y- x^ 2 2 +c

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