The solution of the equation d y d x = (1+x) y (y-1) x is :
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the equation \(\frac{d y}{d x}=\frac{(1+x) y}{(y-1) x}\) is :
- log xy + x + y = c
- log \(\left(\frac{\mathrm{x}}{\mathrm{y}}\right)\) + x – y = c
- log xy + x – y = c
- none of these
Answer
(C) log xy + x – y = c
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