The solution of the equation d y d x = (1+x) y (y-1) x is :

Mathematics · JEE Main · NTA ExamsDifferential Equations

The solution of the equation \(\frac{d y}{d x}=\frac{(1+x) y}{(y-1) x}\) is :
  1. log xy + x + y = c
  2. log \(\left(\frac{\mathrm{x}}{\mathrm{y}}\right)\) + x – y = c
  3. log xy + x – y = c
  4. none of these

Answer

(C) log xy + x – y = c

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