The general solution of the differential equation y(x 2 y + e x ) dx – e x dy = 0 is

Mathematics · JEE Main · NTA Exams — Differential Equations

1. x³y – 3e^x = cy
2. x³y + 3e^x = 3cy
3. y³x – 3e^y = cx
4. y³x + 3e^y = cx

Answer

(B) x 3 y + 3e x = 3cy

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